96b^2-6=0

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Solution for 96b^2-6=0 equation:



96b^2-6=0
a = 96; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·96·(-6)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*96}=\frac{-48}{192} =-1/4 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*96}=\frac{48}{192} =1/4 $

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